I am new to college and I am an oldie and never had the stuff I am learning now. I was wandering if someone can help me with this problem.
I need to do this,
solve: 2(x-1)-3 = -3x +2
I most definately appreciate any help with this.
Solve: 2(x-1)-3 = -3x +2Originally Posted by old & new
First expand the bracketed term to give:
2x - 2 - 3 = -3x + 2,
2x - 5 = -3x + 2.
Now add 3x to both sides to give:
2x + 3x - 5 = -3x + 3x +2,
5x - 5 = 2.
Now add 5 to both sides:
5x - 5 + 5 = 2 + 5,
5x = 7.
Now divide both sides by 5 to give:
(5x)/5 = 7/5,
x = 7/5 = 1.4.
Reality check: put x=1.4 in to the LHS of:
2(x-1)-3 = -3x +2
2(0.4) - 3 = -2.2.
Now put x=1.2 into the RHS gives:
-3*1.4 + 2 = -2.2
which checks out (note in this last expression I have used *
as the multiply symbol to avoid confusion with the decimal point
and x as a variable label).
Can someone tell me if I did this right.
Translate into a mathematical expression:
the difference between ten and the quotient of a number and five.
is that right?
Here is another one
translate: the sum of fifteen and the product of twelve and x.
15 + 12x ??????
translate into an equation and slove.
five less than the product of a number and two is seventeen.
Translate in an equation and solve:
five more than the quotient of a number and three is eight..
I need help with this one. I came up with x/3 + 5 = 8
I need to sove it but have no idea what I am doing.
I need help with them all
Before I go, here is another...
solve: 2x - 6(x-2) = 3(x-4)
Thank You so much. I am not here looking for someone to give me the answers, I need help with how to do this stuff.