I take it by you mean .
Then on we have a group operation: .
Then: is a homomorphism . Work the details out for yourself.
You can even show that the kernel of this homomorphism is trivial. ker . After that apply the isomorphism-theorem.
Am I supposed to guess that?
you couldve meant anything with .
is a group, is a group. And yes is a group too. Provide these details next time.
Anyway, yes these groups are isomorphic:
with inverse is a homomorphism: . The kernel is of this homomorphism is trivial, namely:
The isomorphism theorem gives: