Hi, one one of the elementary row operations, is the addition of a multiple of on equation to another equation. This operation will not change the value of a matrix, but I do not understand why. I would also like to know, if there is any graphical representation, to illustrate this concept.
Thanks for your help”
It is clear from the way we reduce a system that if a certain set of numbers satisfies the original system, then they also satisfy the reduced system. Turn the roles of original & reduced matrices around: If we start by the reduced system, we can obtain the original system by a combination of elementary row operations. Then clearly, any solution of the reduced system is also a solution of the original.
Therefore, it's proved that elementary row operations, when applied to the matrix of a linear system, do NOT change the solution set of that system.
Another way of looking at it: think of the system of equations the matrix represents. The three row- operations correspond to operations on the equations:
"Swap two rows" is just "swap the positions of two equations". Obviously that will not change the solution set of the equations.
"Multiply a row by a (non-zero) constant" is "multiply each term of the equation by the same number". Since you are multiplying both sides of the equation by the same thing, this does not change the solution set.
"Add a multiple of one row to another" is a bit more complicated. It is a combination of "multiply one equation by a constant" and "add this new equation to another equation in the set". The first does not change the solution set because we are multiplying both sides of the equation by the same thing. The second does not change the solution set because both sides of the first equation are equal and so we are adding the same thing to both sides of the second equation.