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Math Help - HNC Maths Help

  1. #1
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    HNC Maths Help

    Not sure if I have posted this in the right place, so I aplogise if I havn't.

    I have started doing a HNC course in Engineering and the first topic is Analytical Methods for Engineers. It is a self learning course, I don;t go to any lectures or get to see people for guidance, the only help I get is a booklet of lessons. I have worked through this but I am still struggling.

    Maths has never been my strongest subject so it would be much appreciated if anyone could point me in the right direction with any of this question:

    The age of a machine, x, in years is related to the probablity of breakdown, y, by the formula:

    ..................y
    x = 3 + ln [ ___ ]
    ................1 - y



    Determine the probablity of breakdown for 1, 3 and 10 years.
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  2. #2
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    Quote Originally Posted by JP103 View Post
    Not sure if I have posted this in the right place, so I aplogise if I havn't.

    I have started doing a HNC course in Engineering and the first topic is Analytical Methods for Engineers. It is a self learning course, I don;t go to any lectures or get to see people for guidance, the only help I get is a booklet of lessons. I have worked through this but I am still struggling.

    Maths has never been my strongest subject so it would be much appreciated if anyone could point me in the right direction with any of this question:

    The age of a machine, x, in years is related to the probablity of breakdown, y, by the formula:

    ..................y
    x = 3 + ln [ ___ ]
    ................1 - y



    Determine the probablity of breakdown for 1, 3 and 10 years.

    So it seems to be that you've to calculate y in each of the cases x =1,3,or 10. Let's do the first one, and you do the following ones:

    1=3+\ln\left(\frac{y}{1-y}\right)\Longrightarrow \ln\left(\frac{y}{1-y}\right)=-2\Longrightarrow \frac{y}{1-y}=e^{-2} \Longrightarrow y\left(1+e^{-2}\right)=e^{-2}\Longrightarrow y=\frac{e^{-2}}{\left(1+e^{-2}\right)}\cong 0.1192

    Tonio
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  3. #3
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    Jan 2010
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    Thanks alot for that. I've done the other two as well now.
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