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Thread: Find Argument, probably easy

  1. November 9th 2005, 01:32 AM #1
    coba
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    Find Argument, probably easy

    if you got z=(-1-sqrt(3)*i)^101
    Find arg(z) the answer should be between 0 and 2pi
    I just dont get it right no matter how i do...
    PLZ help
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  2. November 9th 2005, 03:36 AM #2
    CaptainBlack
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    Quote Originally Posted by coba
    if you got z=(-1-sqrt(3)*i)^101
    Find arg(z) the answer should be between 0 and 2pi
    I just dont get it right no matter how i do...
    PLZ help
    Write -1-\sqrt(3)\cdot i in polar form,
    then you will see that arg(z) is 101
    times arg(-1-\sqrt(3)\cdot i) reduced
    modulo 2 \cdot \pi .

    RonL
    Last edited by MathGuru; December 3rd 2005 at 05:29 PM.
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