if you got z=(-1-sqrt(3)*i)^101

Find arg(z) the answer should be between 0 and 2pi

I just dont get it right no matter how i do... :mad:

PLZ help

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- Nov 9th 2005, 01:32 AMcobaFind Argument, probably easy
if you got z=(-1-sqrt(3)*i)^101

Find arg(z) the answer should be between 0 and 2pi

I just dont get it right no matter how i do... :mad:

PLZ help - Nov 9th 2005, 03:36 AMCaptainBlackQuote:

Originally Posted by**coba**

then you will see that $\displaystyle arg(z) $ is 101

times $\displaystyle arg(-1-\sqrt(3)\cdot i) $ reduced

modulo $\displaystyle 2 \cdot \pi $.

RonL