# Find Argument, probably easy

• November 9th 2005, 02:32 AM
coba
Find Argument, probably easy
if you got z=(-1-sqrt(3)*i)^101
Find arg(z) the answer should be between 0 and 2pi
I just dont get it right no matter how i do... :mad:
PLZ help
• November 9th 2005, 04:36 AM
CaptainBlack
Quote:

Originally Posted by coba
if you got z=(-1-sqrt(3)*i)^101
Find arg(z) the answer should be between 0 and 2pi
I just dont get it right no matter how i do... :mad:
PLZ help

Write $-1-\sqrt(3)\cdot i$ in polar form,
then you will see that $arg(z)$ is 101
times $arg(-1-\sqrt(3)\cdot i)$ reduced
modulo $2 \cdot \pi$.

RonL