Find Argument, probably easy

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November 9th 2005, 01:32 AM
coba

Find Argument, probably easy

if you got z=(-1-sqrt(3)*i)^101
Find arg(z) the answer should be between 0 and 2pi
I just dont get it right no matter how i do... :mad:
PLZ help
November 9th 2005, 03:36 AM
CaptainBlack

Quote:

Originally Posted by coba

if you got z=(-1-sqrt(3)*i)^101
Find arg(z) the answer should be between 0 and 2pi
I just dont get it right no matter how i do... :mad:
PLZ help

Write $-1-\sqrt(3)\cdot i$ in polar form,
then you will see that $arg(z)$ is 101
times $arg(-1-\sqrt(3)\cdot i)$ reduced
modulo $2 \cdot \pi$ .

RonL

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