Let and . Find value and hence deduce the when

here my calculations are

.......

Is that above answer is true?

But I saw in other way like and then bt I couldn't understand this..

Printable View

- Dec 31st 2009, 07:22 PMdhammikaiRecurrence relation question
Let and . Find value and hence deduce the when

here my calculations are

.......

Is that above answer is true?

But I saw in other way like and then bt I couldn't understand this.. - Jan 1st 2010, 07:25 AMHallsofIvy
(0.5+ 0.2i)^2= 0.5^2- 0.2^2+ (2(0.5)(0.2))i= 0.21+ .2i so (0.5+ 0.2i)+ 2i= 0.21+ 2.2i. You seem to have dropped the hundredths place and that might be important.

Quote:

.......

Is that above answer is true?

But I saw in other way like and then bt I couldn't understand this..

Unfortunately, that "polar form" doesn't work well with addition so you would have to change back each time to add the "2i".

In fact, that recursion formula is the one used in calculating Julia sets and the Mandelbrot set so I don't see any method other than 'brute strength" calculation nor do I see that knowing will tell you very much about the limit as n goes to infinity. - Jan 3rd 2010, 08:17 PMdhammikai
Thank you very much "HallsofIvy" now I have a clear answer. Thanks