Let G be a finite group, and let S and T be 2 subsets of G such that G does not equal ST. Show that![]()
There are |S| elements in S. There are |T| elements in, and also in its coset
. Also, the sets S and
are disjoint: for suppose that an element
is also in
. Then
for some
. But that implies that
, which contradicts the choice of g. Therefore there are |S|+|T| distinct elements in the set
, and so
.