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Math Help - Linear functionals

  1. #1
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    Linear functionals

    1)Let T:V-->V be any linear map and V* be its dual.Let W be a k-dimensional subspace of V.(V is finite dimensional).Then prove that there exits a Linearly independent subset {f1,f2,...f(n-k)} subset of V* such that W=inetsection of Kernel(fi), where i=1,2,...,n-k.


    2)Let T* denote the adjoint of T. If T is surjective then show that T* is injective
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  2. #2
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    Quote Originally Posted by math.dj View Post
    1)Let T:V-->V be any linear map and V* be its dual.

    You mean: V^{*} is the dual space of V.

    Let W be a k-dimensional subspace of V.(V is finite dimensional).Then prove that there exits a Linearly independent subset {f1,f2,...f(n-k)} subset of V* such that W=inetsection of Kernel(fi), where i=1,2,...,n-k.

    Let \{w_1,\ldots,w_k\} be any basis of W, and let us extend it to a basis \{w_1,\ldots,w_k,w_{k+1},\ldots,w_n\} of V . Let \{f_1,\ldots,f_n\} be the dual basis in V^{*} of the above basis of V , i.e. f_iw_j=\delta_{ij}=\left\{\begin{array}{cc}1&\mbox  {, if }\, i=j\\0&\mbox{, if }\, i\neq j\end{array}\right. .

    Well, now prove that \mbox{ }\,W=\bigcap\limits_{j=k+1}^nKer(f_j)


    2)Let T* denote the adjoint of T. If T is surjective then show that T* is injective
    Ok, so we ALSO have an inner product on V. Assume  T^{*}x=T^{*}y and let be z\in V\,\,\,s.t.\,\,\,Tz=x-y , so:

    <x-y,x-y>=<Tz,x-y>=<z,T^{*}(x-y)>=<z,0> = ...

    Tonio
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