Originally Posted by

**tbird** alright...so i'm a 100% lost.

my pathetic attempt:

$\displaystyle 6x + 12$ must be 0.

so, im thinking that 'plug a into x, so that once the equation is solved i can then reduce the final value to fit in $\displaystyle \mathbb{Z}\slash a\mathbb{Z}[x]$'

i ran over a bunch in my head, and if what i said above is right, then factors of 12 = a

so, a = 1, 2, 3, 4, 6, and 12

(the math to my argument for a=6 -- a=x so (6)(6) + 12 = 48, but 48 must live in $\displaystyle \mathbb{Z}\slash 6\mathbb{Z}[x]$ which is 0, voila)

?? right track ??