1. ## Velocity and Acceleration

Hello!
This question is about the function:
v = 50 - 50e^(-0.2t), t is bigger or the same as 0.
v is in metres per second and t is in seconds.

The problem is to find:
a) i- an expression for the acceleration, a, as a function of t.
ii - What is the value of a when t = 0?

also,
d) Let y metres be the distance fallen after t seconds.
i) show that y = 20t + 250e^(-0.2t) + k, where k is a constant.

2. (i) $v=50 - 50e^{-0.2t}$ and $a=\frac{dv}{dt}$
(ii) when you get $a$ as a function of $t$, put $t = 0$
(iii) $v=\frac{dy}{dt}$, so $y=\int v dt=\int50 - 50e^{-0.2t} dt$