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Math Help - Velocity and Acceleration

  1. #1
    Junior Member
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    Smile Velocity and Acceleration

    Hello!
    This question is about the function:
    v = 50 - 50e^(-0.2t), t is bigger or the same as 0.
    v is in metres per second and t is in seconds.

    The problem is to find:
    a) i- an expression for the acceleration, a, as a function of t.
    ii - What is the value of a when t = 0?

    also,
    d) Let y metres be the distance fallen after t seconds.
    i) show that y = 20t + 250e^(-0.2t) + k, where k is a constant.

    I would appreciate your help,
    best wishes Amine
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  2. #2
    Senior Member
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    (i) v=50 - 50e^{-0.2t} and a=\frac{dv}{dt}

    (ii) when you get a as a function of t, put t = 0

    (iii) v=\frac{dy}{dt}, so y=\int v dt=\int50 - 50e^{-0.2t} dt
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