(ii) when you get as a function of , put
(iii) , so
This question is about the function:
v = 50 - 50e^(-0.2t), t is bigger or the same as 0.
v is in metres per second and t is in seconds.
The problem is to find:
a) i- an expression for the acceleration, a, as a function of t.
ii - What is the value of a when t = 0?
d) Let y metres be the distance fallen after t seconds.
i) show that y = 20t + 250e^(-0.2t) + k, where k is a constant.
I would appreciate your help,
best wishes Amine