Hi. I`m new here, so hope I can get some help. Did a search but didnt find anything on it.

Anybody can help me find Matrix A power 5 using Caley Hamilton theorem (no other option allowed here).

A=[1 1 -1

1 1 1

1 1 1]

Thanks!

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- Dec 2nd 2009, 11:42 PMmolokomesto650How to find matrix A power 5 using caley hamilton theorem?
Hi. I`m new here, so hope I can get some help. Did a search but didnt find anything on it.

Anybody can help me find Matrix A power 5 using Caley Hamilton theorem (no other option allowed here).

A=[1 1 -1

1 1 1

1 1 1]

Thanks! - Dec 3rd 2009, 02:47 AMmr fantastic
- Dec 3rd 2009, 03:55 AMmolokomesto650
that would be (unless mistake)

- λ^3+3 λ^2-2 λ - Dec 3rd 2009, 05:24 AMdedust
the characteristic equation is $\displaystyle p(\lambda)=\lambda^3-3\lambda^2+2\lambda$

so

$\displaystyle A^3-3A^2+2A=0$

and

$\displaystyle A^5=3A^4-2A^3$ - Dec 3rd 2009, 06:38 AMmolokomesto650
thanks to both of you. Very helpful.