1. ## Multiplicative Inverse

Find the multiplicative inverse in the given field.

$[x^2-2x+1]$ in $Z_3[x]/$

Thank you!

2. Hint: $\mathbb{Z}_{3}[x]{/}(x^3 + x^2 +2x + 1)$ = $\{0,1,2,x,x+1,x+2,2x,2x+1,2x+2,x^2,x^{2} +1, x^{2}+2,x^{2}+x,x^{2}+2x,x^{2}+x+1,$ $x^{2}+x+2,x^{2}+2x+1,x^{2}+2x+2\}$

And $x^2 -2x +1 = x^2 +x + 1$

3. I think I've got it!
Is the answer (x-2) (or should I say x+1?)?

Correct me if I've done this wrong, but:
x^2-2x+1)(x-2)=x^3-2x^2+x-2x^2+4x-2
=x^3-4x^2+5x-2
=x^3+x^2+2x+1