Find the multiplicative inverse in the given field. in Thank you!
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Hint: = And
I think I've got it! Is the answer (x-2) (or should I say x+1?)? Correct me if I've done this wrong, but: x^2-2x+1)(x-2)=x^3-2x^2+x-2x^2+4x-2 =x^3-4x^2+5x-2 =x^3+x^2+2x+1
Last edited by elninio; Dec 2nd 2009 at 10:47 AM.
Actually, it seems I am going about this the wrong way. I am trying the find an a^-1 in which: a*a^-1=1 in Z_3. where a=x^2+x+1 Is this right? By doing a case by case basis I still cant find a suitable answer.
I'm not sure if I'm allowed to bump this, but it would be nice to have an answer. Thank you!
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