can anyone help me with this question

solve completely the following system

x+2y+mz=0

2x+3y-2z=m

mx+y+m^2z=3

Im a bit stumped on what to do with the m? any help would be appreciated

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- Nov 30th 2009, 02:54 PMprincessamme@hotmail.comlinear equation help
can anyone help me with this question

solve completely the following system

x+2y+mz=0

2x+3y-2z=m

mx+y+m^2z=3

Im a bit stumped on what to do with the m? any help would be appreciated - Nov 30th 2009, 04:35 PMpickslides
Solve this

- Dec 1st 2009, 05:51 AMHallsofIvy
If you don't want to use matrices, you can just solve it as you would in basic algebra: Multiplying the first equation by m and subtracting from the third equation elimnates both x and z: (m- m)x+ (1- 2m)y+ (m^2- m^2)z= 3- 0 so (1- 2m)y= 3. If , . Put that value of y into the first and second equations to get two equations for x and z. if m= 1/2, 1- 2m= 0 so there is no solution.

- Dec 1st 2009, 06:11 AMRaoh
hi(Happy)

Using Gauss method,

in case ,there will be no solution.

in case ,you'll have , substitute and get the other values . - Dec 1st 2009, 06:23 AMRaoh
- Dec 2nd 2009, 07:34 AMprincessamme@hotmail.com
Thank you for all your help, I originally used gaussian elimination, however i could get a nice solution so i assumed what i was doing was wrong (Happy)