The first is pretty straight forward. In general, to prove " " you show: "if y is a member of A then y is a member or B".

Here you want to prove:

If y is in Im(S+ T) then y= (S+ T)x for some x in V. But "(S+ T)x" isdefinedas Sx+ Tx so we have y= Sx+ Tx. Let and . Then is in Im(S), is in Im(T), and . Therefore, y is in Im(S)+ Im(T). The rest of that should be straight forward.

The second may be even simpler. Saying "ST= 0" mean (ST)v= 0 for all v. But that is the same as S(Tv)= 0 so that Tv is in the kernel of S for all v.