If G=<a> is a cyclic group of order m generated by an element a∈G, then for each divisor r of m exhibit explicitly an element c∈G of order r.
Last edited by mr fantastic; Nov 21st 2009 at 09:05 PM.
Reason: Changed post title
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Have you even tried this? This really isn't too hard. It doesn't even ask you to show that the element you find with order is unique. If what can we say about ?
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