Thread: Galois Theory

Consider the automorphisms of k(x) defined by s1(x) = x (the
identity), s2(x) = 1 - x and s3(x) = 1/x. Show that these generate a group
G of order exactly 6 and that the remaining automorphisms are s4(x) = 1 -
(1/x); s5(x) = 1/(1 - x), and s6(x) = x/(x - 1).

Assuming the fundamental theorem of the Galois theory, exhibit
all the intermediate fields between E = k(x) and F = k(I).
I(x)= (x^2-x+1)^3 / (x^2*(x-1)^2)


Also Show I(x) is invariant under the group G

Originally Posted by dabien

Assuming the fundamental theorem of the Galois theory, exhibit
all the intermediate fields between E = k(x) and F = k(I).

What is I? Is k any field? Is k(x) the field of rational functions over k?

Tonio

i fixed it.

Originally Posted by dabien

i fixed it.

I don't have the slightest idea what you mean, and if you think you answered my questions then mind you: you didn't.

Tonio