A = [1 -2 -1]
A = [2 -3 1]
A = [-3 5 0]
B = [0 1 0]
B = [-1 3 2]
B = [1 -4 -2]
find one matrix X such that AX = B.
A and B are 3x3 matrix above
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Originally Posted by Krizalid But A and B both end up with a row of zeros, they don't have an inverse.
B doesn't need to be invertible, just A, and A is invertible.
Originally Posted by Krizalid B doesn't need to be invertible, just A, and A is invertible. How is A invertible? Won't one find a row of zeroes on the left-hand side of the augmented matrix, implying that A is singular? Incidentally, the same situation will arise with B.
what's its determinant?
Originally Posted by Krizalid what's its determinant? Such that it's not invertible.
ohh, i just realized that i got a typo in the third row when computing the determinant.
anyway, there's no X, but at least the OP knows now how to solve the problem.
I have got the solution for the question,
X = [-2 3 4]
X = [-1 1 2]
X = [0 0 0 ]
thanks for the help
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