I cannot get the correct answer to this question..any help would be greatly appreciated. Thanks in advance

Let P1 be the plane defined by:

(-2,0,2), (5,-1,5) and (0,2,4)

Find the equation of the plane perpendicular to P1 and containing the line:

(x,y,z)=(0,-1,-3)+ t(-1,3,-3)

Answer should be in the form Ax+By+Cz-D=0

So first i found the equation for plane P1 as -8x-8y+16z-48=0

I do not really know where to go from here.

thanks