eigenspaces/diagonalizability

Quote:

Originally Posted by dannyboycurtis

Hey y'all I got a question regarding eigenspaces which is stumping me. Heres the problem, any tips or help would be greatly appreciated.

Let T be an invertible linear operator on a finite-dimensional vector space V.
Prove that the eigenspace of $T$ corresponding to $\lambda$ is the same as the eigenspace of $T^{-1}$ corresponding to $\lambda ^{-1}$

Also prove that if $T$ is diagonalizable, then $T^{-1}$ is diagonalizable.

Thanks!

*********sigh********....really!(Headbang)(Punch)

$Tv=\lambda v\Longrightarrow (apply\,\,T^{-1}\,\,on\,\,both\,\,sides)\,v=T{-1}(\lambda v)$ , and now just use that the inverse of a linear map is also linear.
For diagonalizable: use the definition, apply, move sides...etc.

Tonio