Haha, how does my proof look?

Q- If K is normal to H and H is normal to G show that for all a in G.

Pf:

Let and . Now, if then . Now, pull out the inverse . This gives . Since we have . and thus as desired.

Printable View

- November 7th 2009, 09:44 AMsfspitfire23How does my elegantly cradfted proof look?
Haha, how does my proof look?

Q- If K is normal to H and H is normal to G show that for all a in G.

Pf:

Let and . Now, if then . Now, pull out the inverse . This gives . Since we have . and thus as desired.