# Thread: Show that T^kU = UT^k

1. ## Show that T^kU = UT^k

Hello,
i would like help with this:
Assume that T : V ....> V is linear and that n and k are positive integers and that a_0,a_1,a_2,.....,a_n are scalars. Let U = a_0IV + a_1T + a_2T^2 +  + a_nT^n. Show that T^kU = UT^k.
Use from 1 to 6:
(1) Since
L(V, V ) is a vector space all of the vector space properties hold for addition and scalar multiplication.
(2)
T(U1U2) = (TU1)U2.
(3) )
T(U1 + U2) = (TU1) + (TU2).
(4) (U1 + U2)T = U1T + U2T.
(5) For any non-negative integers
i and j, T^iT^j = T^i+j .

(6) For any scalars
c and d, (cT )(dU1) = (cd)TU1.

Thank you

2. Originally Posted by Nona Hello,
i would like help with this:
Assume that T : V ....> V is linear and that n and k are positive integers and that a_0,a_1,a_2,.....,a_n are scalars. Let U = a_0IV + a_1T + a_2T^2 + + a_nT^n. Show that T^kU = UT^k.
Use from 1 to 6:

(1) Since
L(V, V ) is a vector space all of the vector space properties hold for addition and scalar multiplication.

(2)

T(U1U2) = (TU1)U2.

(3) )

T(U1 + U2) = (TU1) + (TU2).

(4) (U1 + U2)T = U1T + U2T.

(5) For any non-negative integers

i and j, T^iT^j = T^i+j .
(6) For any scalars c and d, (cT )(dU1) = (cd)TU1.

Thank you

This is trivial using the given definitions. For example, with k = 2 we get:

$\displaystyle T^2U=T^2(a_0I+a_1T+...+a_nT^n)=T\left[T\left(\sum\limits_{i=0}^na_iT^i\right)\right]=$ $\displaystyle T\left(\sum\limits_{i=0}^na_iT^{i+1}\right)=\sum\l imits_{i=0}^na_iT^{i+2}$

$\displaystyle UT^2=(UT)T=\left[\left(\sum\limits_{i=0}^na_iT^{i}\right)T\right]T$ $\displaystyle =\left[\sum\limits_{i=0}^na_iT^{i+1}\right]T=\sum\limits_{i=0}^na_iT^{i+2}$

Now just apply a simple induction here and you're done.

Tonio

3. Thank you very much.
Is that means: changing 2 to k.
I have to use all the properties from 1 to 6

4. Originally Posted by Nona Thank you very much.
Is that means: changing 2 to k.
I have to use all the properties from 1 to 6

Well, in fact you need them more than anything else to fully justify the first case which we already did above. For the case k you must assume that it is true for k-1 and then use induction...and yes, still some of the properties 1-6 given.

Tonio

5. Thank you very much.
Will try to do it.

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