Show that for every mapping , that there exists a polynomial such that for all

I'm pretty sure Lagrange Interpolation is what is needed here but I'm not sure how to use it.

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- Nov 4th 2009, 09:23 AMHavenMappings and Polynomials
Show that for every mapping , that there exists a polynomial such that for all

I'm pretty sure Lagrange Interpolation is what is needed here but I'm not sure how to use it. - Nov 4th 2009, 09:51 AMclic-clac
Yes since the sets used are finite with the same cardinal and that is a group for (I assume denotes a prime) you can write something like

, and it is an element of