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Math Help - linear system

  1. #1
    Super Member
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    Smile linear system

    hi
    i have the following system.
    x+2y+3z+4t+5u=6
    x+3y+5z+7t+4u=13
    x+4y+7z+10t+3u=20
    x+2y+4z+6t+8u=13
    with Gauss method,i ended up here,
    x+2y+3z+4t+5u=6
    y+2z+3t-u=7
    z+2t+3u=7
    i don't know how to work with the parameters t and u.
    thanks.
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by Raoh View Post
    hi
    i have the following system.
    x+2y+3z+4t+5u=6
    x+3y+5z+7t+4u=13
    x+4y+7z+10t+3u=20
    x+2y+4z+6t+8u=13
    with Gauss method,i ended up here,
    x+2y+3z+4t+5u=6
    y+2z+3t-u=7
    z+2t+3u=7
    i don't know how to work with the parameters t and u.
    thanks.
    Use t and u as free parameters and solve for x, y and z in terms of them.

    Start with z, from the last equation z=7-2t-3u, now do y and then x.

    CB
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  3. #3
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    Smile

    okay,so for every value u and t,the system has a unique solution,
    x = -1-10u, y= -7 +t + 7u and z = 7 -2t -3u.
    is it okay ?
    thanks.
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  4. #4
    MHF Contributor

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    Yes, that is what I get.
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  5. #5
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    Smile

    by the way,is my Gauss method correct,did anyone check it
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  6. #6
    MHF Contributor

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    I hadn't before but I just did. Yes, that is correct.
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