hi(Happy)

i have the following system.

x+2y+3z+4t+5u=6

x+3y+5z+7t+4u=13

x+4y+7z+10t+3u=20

x+2y+4z+6t+8u=13

with Gauss method,i ended up here,

x+2y+3z+4t+5u=6

y+2z+3t-u=7

z+2t+3u=7

i don't know how to work with the parameters and .

thanks.

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- October 31st 2009, 09:50 AMRaohlinear system
hi(Happy)

i have the following system.

x+2y+3z+4t+5u=6

x+3y+5z+7t+4u=13

x+4y+7z+10t+3u=20

x+2y+4z+6t+8u=13

with Gauss method,i ended up here,

x+2y+3z+4t+5u=6

y+2z+3t-u=7

z+2t+3u=7

i don't know how to work with the parameters and .

thanks. - November 1st 2009, 01:48 AMCaptainBlack
- November 1st 2009, 03:37 AMRaoh
okay,so for every value and ,the system has a unique solution,

and .

is it okay ?

thanks. - November 1st 2009, 03:53 AMHallsofIvy
Yes, that is what I get.

- November 1st 2009, 03:57 AMRaoh
by the way,is my Gauss method correct,did anyone check it(Happy)

- November 1st 2009, 05:31 AMHallsofIvy
I hadn't before but I just did. Yes, that is correct.