Show that x^n = (a_i) where a_i = { 1 if i = n, 0 if otherwise| for all n >= 0}
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So now I have: x = (ai) where ai = { 1 if i = 1, 0 if i <> 1 x(bi) = (ai)(bi) = (di) where di = sum from j=0 to i of aj(bi-j) = a1(bi-1) = 1(bi-1) = bi-1, since aj=0 if j<>1 but I don't know where to go from here..
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