Find a basis for the subspace R3 defined by

{(3a,5b,2a-b): a,b are members of R}

- October 27th 2009, 09:29 AMpasleycakesFind a basis for the subspace R3 defined by {(3s,5b,2a-b):a,b R}
Find a basis for the subspace R3 defined by

{(3a,5b,2a-b): a,b are members of R} - October 27th 2009, 09:54 AMSwlabr
What is " "?

When you are given a set in a general form you can quite easily come up with a spanning set. You just split up the general form into vectors containing one and only one of the variables. For instance, " ", and then take out the variables and you will have yous spanning set. So here " " would become " " which is a member of your spanning set.

You then have to ask if this spanning set is a basis or not. That is, is it linearly independent. - October 28th 2009, 06:43 AMHallsofIvy
- October 28th 2009, 07:13 AMSwlabr
- October 28th 2009, 04:35 PMmath2009

So basis - October 28th 2009, 11:43 PMSwlabr
- October 29th 2009, 04:00 PMmath2009
- October 30th 2009, 12:43 AMSwlabr