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Thread: morphism

  1. Oct 22nd 2009, 07:51 PM #1
    sfspitfire23
    sfspitfire23 is offline
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    morphism

    If I have a mapping under addition \alpha : \mathbb{z} \rightarrow \mathbb{z} given by \alpha(h(x))=h'(x)

    to show it would I do this-

    \alpha(h(x)+k(x))=\alpha h(x) + \alpha k(x)

    Then when mapping is applied h'(x)+k'(x)=h'(x)+k'(x) and this shows that \alpha : \mathbb{z} \rightarrow \mathbb{z} \alpha(h(x))=h'(x) is a homomorphism? or is there more?
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  2. Oct 22nd 2009, 11:44 PM #2
    el_manco
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    Re: morphism

    Hello

    Your proof is correct. I suppose that your are considering F only with que strucuture of group given by the usual adittion of funcitons.

    Best regards.
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