If $\displaystyle B = PAP^{-1}$

show that: $\displaystyle tr(A) = tr(B)$(Itwasntme)

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- Oct 20th 2009, 08:03 AMXingyuanTrace about similar matrix
If $\displaystyle B = PAP^{-1}$

show that: $\displaystyle tr(A) = tr(B)$(Itwasntme) - Oct 20th 2009, 08:45 AMaman_cc