Suppose that ф: Z50 → Z50 is an automorphisim with ф(11) = 13. Determine a formula for ф(x).

Results 1 to 4 of 4

- Oct 18th 2009, 06:08 AM #1

- Joined
- Jul 2009
- Posts
- 21

- Oct 18th 2009, 06:26 AM #2

- Joined
- Apr 2009
- Posts
- 678
- Thanks
- 1

- Oct 18th 2009, 06:59 AM #3

- Joined
- Jul 2009
- Posts
- 21

- Oct 18th 2009, 07:18 AM #4

- Joined
- Apr 2009
- Posts
- 678
- Thanks
- 1

How did you get that? You need to be careful when you are using symbols ^ and x

Can you express 1 as a power of 11? (Note:**by power here we mean repeated application of group operation so 11^5 = 5**). Say it is 'n'

Once you know that ф(1)= ф(11^n) = ф(11)^n

Once we know ф(1), ф(x) should be easy, right?