If $\displaystyle A=\left[ \begin{matrix} 2 & 1 & 1 \\ 1 & 2 & 0 \\ 1 & 1 & 2 \end{matrix} \right]$, then $\displaystyle A^{2009}=...$
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Originally Posted by GTK X Hunter If $\displaystyle A=\left[ \begin{matrix} 2 & 1 & 1 \\ 1 & 2 & 0 \\ 1 & 1 & 2 \end{matrix} \right]$, then $\displaystyle A^{2009}=...$ Did you try computing A^1, A^2, A^3? ....most probably if you do that you shoud see a pattern that you can use?
Originally Posted by aman_cc Did you try computing A^1, A^2, A^3? ....most probably if you do that you shoud see a pattern that you can use? yeap i have done it but i cant see any pattern... please help... may be use another way besides try computing A^1, A^2, A^3, ... ?
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