If $\displaystyle A=\left[ \begin{matrix} 2 & 1 & 1 \\ 1 & 2 & 0 \\ 1 & 1 & 2 \end{matrix} \right]$, then $\displaystyle A^{2009}=...$

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- Oct 18th 2009, 12:43 AMGTK X Hunterpolynomial matrix - help me^_^
If $\displaystyle A=\left[ \begin{matrix} 2 & 1 & 1 \\ 1 & 2 & 0 \\ 1 & 1 & 2 \end{matrix} \right]$, then $\displaystyle A^{2009}=...$

- Oct 18th 2009, 12:50 AMaman_cc
- Oct 18th 2009, 02:47 AMGTK X Hunter