Hello, I am stuck with the following question:
Show that is not ring-isomorphic to .
Do NOT use a cardinality argument.
Hint: suppose you had a ring isomorphism , look at
Thanks in advance
any ring homomorphism has to send 1 to one. Because it is a ring Hom, it has to preserve addition, so it must send the integers to the integers. We also have for the rational numbers in the reals, it must send them to the same thing in the rationals because of this.
But this show we already have the rational numbers inside of the reals mapping onto the rationals, so this must go into the rationals somewhere and this will contradict the injectivity of any possible isomorphism, since there are two things going to wherever phi sends