Stupid inequality i can't solve, we've been told to show a certain method when solving the question which i don't understand T_T

Question

$\displaystyle \frac{3}{3x-2}>\frac{1}{x+4}$

The method we are meant to use is supposed to involved these if statements (4 of them)

1. If (x+4)(3x-2) are +ve then ans is ....

2. If (x+4)(3x-2) are -ve then ans is ....

3. If (x+4) is +ve and (3x-2) is -ve then ans is ....

4. If (3x-2) is +ve and (x+4) is -ve then ans is ....

I think i can do the 1st if statement

$\displaystyle \frac{3}{3x-2}>\frac{1}{x+4}$

If both denominators +ve multiply both sides by (x+4)(3x-2) which results in.

$\displaystyle 3(x+4)>3x-2$

$\displaystyle 3x+12>3x-2$

$\displaystyle 14>0$

Got no idea how to do 2.3.4 someone help meee

1.