Show that span(v1,.., vn) is the smallest subspace of V that contains all the vectors in the list (v1,.., vn)...

i proved that the span is subspace, i need help on the smallest

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- Oct 8th 2009, 10:45 PMmancillaj3smallest subspace of VShow that span(v1,.., vn) is the smallest subspace of V that contains all the vectors in the list (v1,.., vn)...

i proved that the span is subspace, i need help on the smallest - Oct 8th 2009, 11:42 PMaman_cc
Let L = span(v1,.., vn)

Let W be a subspace of V smaller than L. i.e. there is a vector 'x' in L [i.e. x is a linear combination of (v1,.., vn)] which is not in W

This leads to a contradiction under two facts about W:

1. W is a sub-space

2. W contains (v1,.., vn)

Under this contradiction - we can say any subspace with (v1,v2,,,vn) will have L as a subspace.