1. ## Permutation confusion

any enlightenment about this would be great I dont know whether the permutation moves A to where B is in the first picture or if we apply the function to A it becomes C.

2. Originally Posted by slevvio
any enlightenment about this would be great I dont know whether the permutation moves A to where B is in the first picture or if we apply the function to A it becomes C.

Is the one from the left: why do you think it could be the right one, anyway??

Tonio

3. because A goes to where B is in the original triangle, B goes to where C is and C goes to where A is

also this is meant to be an example of one of the rotations in the dihedral group for an equilateral triangle

4. Originally Posted by slevvio
because A goes to where B is in the original triangle, B goes to where C is and C goes to where A is

Oops! Now that you say that I see both possibilities can happen. I guess it all depends on definitions: are we to understand that the vertices are moved (together with their tag = letter) or else the vertices are kept fixed and we move only the letters??
In the first case the right option is correct, since vertex A is moved to position prviously occupied by vertex B, but in the second case the left one is the correct one.

Tonio

5. hehe thanks also those two are inverses of each other which is interesting hehe. I will find out what convention gets used at this university but thanks for the help

6. It's not something to get hung up on - the group $\displaystyle S_3 = D_3$ or whatever it gets called is generally used only for training purposes, as are the diagrams that illustrate the permutations. So whichever convention is being used, you'll be off them quicker than training wheels on your first pushbike.