[SOLVED] Matrix diagonalization & eigenvectors

Hi

Given a matrix $\displaystyle A \in \mathbb{R}^{3x3} $. it's eigenvalues are $\displaystyle \lambda_{1}=1 \ \ \lambda_{2}=1 \ \ \lambda_{3}=2 $

I know that if i found two eigenvectors with $\displaystyle \lambda_{1} = \lambda_{2} $ and one eigenvector with $\displaystyle \lambda_{3} \Rightarrow A $ is diagonlizable.

But what happend when i get just one eigenvector with $\displaystyle \lambda_{1} = \lambda_{2} $ but two with $\displaystyle \lambda_{3} $ and the three are linearly independent?

is A diagonalizable?

thanks very much