need help with these problem:Find the three consecutive odd intergers whose sum is equal to five more than two times the second largest number among the three
"Find the three consecutive odd intergers..."
Let x = 1st odd integer
So, x+2 = 2nd odd integer
And, x+4 = 3rd odd integer
"whose sum..."
x +(x+2) +(x+4) = 3x +6
"...is equal to five more than two times the second largest number among the three."
3x +6 = 2(x+2) +5
3x +6 = 2x +4 +5
3x -2x = 4 +5 -6
x = 3
Hence,
x+2 = 5
x+4 = 7
Therefore, the 3 cosecutive odd integers are 3,5,7. --------answer.
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Check
Sum = 3+5+7 = 15
15 =? 2(5) +5
15 =? 10 +5
15 =? 15
Yes, so, Ok.
Find the three consecutive odd intergers whose sum is equal to five more than two times the second largest number among the three.
Problems with consecutive numbers can be a little easier if we let x be the MIDDLE number. Then we have x-2 for the 1st, x for the 2nd and x+2 for the 3rd.
(x-2) + x + (x+2) = 2x +5
3x = 2x+5
x = 5