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Math Help - Algebra Intermediate

  1. #1
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    Algebra Intermediate

    need help with these problem:Find the three consecutive odd intergers whose sum is equal to five more than two times the second largest number among the three
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  2. #2
    MHF Contributor
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    "Find the three consecutive odd intergers..."
    Let x = 1st odd integer
    So, x+2 = 2nd odd integer
    And, x+4 = 3rd odd integer

    "whose sum..."
    x +(x+2) +(x+4) = 3x +6

    "...is equal to five more than two times the second largest number among the three."
    3x +6 = 2(x+2) +5
    3x +6 = 2x +4 +5
    3x -2x = 4 +5 -6
    x = 3

    Hence,
    x+2 = 5
    x+4 = 7

    Therefore, the 3 cosecutive odd integers are 3,5,7. --------answer.

    -------
    Check
    Sum = 3+5+7 = 15
    15 =? 2(5) +5
    15 =? 10 +5
    15 =? 15
    Yes, so, Ok.
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  3. #3
    Junior Member
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    Find the three consecutive odd intergers whose sum is equal to five more than two times the second largest number among the three.

    Problems with consecutive numbers can be a little easier if we let x be the MIDDLE number. Then we have x-2 for the 1st, x for the 2nd and x+2 for the 3rd.

    (x-2) + x + (x+2) = 2x +5
    3x = 2x+5
    x = 5
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  4. #4
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    thank you very much,ctelady for your help, , havea good day.
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  5. #5
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    TICBOL thanks a lot for your help, you really know your stuff. heep the good work.
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