1. ## Algebra Intermediate

need help with these problem:Find the three consecutive odd intergers whose sum is equal to five more than two times the second largest number among the three

2. "Find the three consecutive odd intergers..."
Let x = 1st odd integer
So, x+2 = 2nd odd integer
And, x+4 = 3rd odd integer

"whose sum..."
x +(x+2) +(x+4) = 3x +6

"...is equal to five more than two times the second largest number among the three."
3x +6 = 2(x+2) +5
3x +6 = 2x +4 +5
3x -2x = 4 +5 -6
x = 3

Hence,
x+2 = 5
x+4 = 7

Therefore, the 3 cosecutive odd integers are 3,5,7. --------answer.

-------
Check
Sum = 3+5+7 = 15
15 =? 2(5) +5
15 =? 10 +5
15 =? 15
Yes, so, Ok.

3. Find the three consecutive odd intergers whose sum is equal to five more than two times the second largest number among the three.

Problems with consecutive numbers can be a little easier if we let x be the MIDDLE number. Then we have x-2 for the 1st, x for the 2nd and x+2 for the 3rd.

(x-2) + x + (x+2) = 2x +5
3x = 2x+5
x = 5

4. thank you very much,ctelady for your help, , havea good day.

5. TICBOL thanks a lot for your help, you really know your stuff. heep the good work.