need help with these problem:Find the three consecutive odd intergers whose sum is equal to five more than two times the second largest number among the three

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- October 8th 2005, 11:58 AMPanaboyAlgebra Intermediate
need help with these problem:Find the three consecutive odd intergers whose sum is equal to five more than two times the second largest number among the three

- October 8th 2005, 02:20 PMticbol
"Find the three consecutive odd intergers..."

Let x = 1st odd integer

So, x+2 = 2nd odd integer

And, x+4 = 3rd odd integer

"whose sum..."

x +(x+2) +(x+4) = 3x +6

"...is equal to five more than two times the second largest number among the three."

3x +6 = 2(x+2) +5

3x +6 = 2x +4 +5

3x -2x = 4 +5 -6

x = 3

Hence,

x+2 = 5

x+4 = 7

Therefore, the 3 cosecutive odd integers are 3,5,7. --------answer.

-------

Check

Sum = 3+5+7 = 15

15 =? 2(5) +5

15 =? 10 +5

15 =? 15

Yes, so, Ok. - October 8th 2005, 03:09 PMctelady
Find the three consecutive odd intergers whose sum is equal to five more than two times the second largest number among the three.

Problems with consecutive numbers can be a little easier if we let x be the MIDDLE number. Then we have x-2 for the 1st, x for the 2nd and x+2 for the 3rd.

(x-2) + x + (x+2) = 2x +5

3x = 2x+5

x = 5 - October 9th 2005, 05:28 PMPanaboy
thank you very much,ctelady for your help, , havea good day.

- October 9th 2005, 05:30 PMPanaboy
TICBOL thanks a lot for your help, you really know your stuff. heep the good work.