Can someone please help me with this quesion?
If G an abelian Group Prove that (a*b)^n = a^n * b^n
a*a*a*a*...*a*b*b*b*....*b, n times each. This equals a^n * b^n.
Note that it is very important that G is abelian. If not, we cannot rearrange the terms however we like!