Results 1 to 3 of 3

Thread: please help--- word problem

  1. #1
    Aug 2005

    please help--- word problem

    small car and a van share 110 gallons of gas. car gets twice as many miles to the gallon. if the car drove 600 miles and the van drove 800 miles. How many gallons of gas did the van use?

    I believe I know the answer but I'm not sure how to set the problem up in algebraic format.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie mathproblem's Avatar
    Oct 2005
    what about setting it up like this and then solve for Vgal

    1) Cgal + Vgal = 110 gal
    2) (2*600mi)/(Cgal) + (800mi)/(Vgal) = (1400/110)(mi/gal)

    as read the Car gets twice as many miles 2*600mi/Cgal to the gallon
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Global Moderator

    Nov 2005
    New York City
    Let m be the mileage of the van
    Then 2m is the mileage of the car.
    Let g be the gallons the van had
    Then 110-g is the gallons the car had.
    Thus, since the car traveled 600 miles and the van 800 miles we have,
    This is a system of 2 equations, just divide both equations.
    Thus, the truck had 80 gallons and took 10 miles to the gallons, and the car had 30 gallons and took 20 miles to the gallon.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. word problem - the snow plough problem?
    Posted in the Differential Equations Forum
    Replies: 1
    Last Post: Oct 13th 2011, 01:02 PM
  2. Replies: 3
    Last Post: Jan 2nd 2011, 08:20 PM
  3. 1 Word problem and 1 function problem
    Posted in the Algebra Forum
    Replies: 8
    Last Post: Apr 21st 2010, 08:01 AM
  4. Replies: 2
    Last Post: Jan 10th 2009, 05:49 AM

Search Tags

/mathhelpforum @mathhelpforum