given that 4^x=8^2-x find the value of x (x is a power)
ooook see what u can do
x is a power.
Okay.
4^x = 8^(2-x)
(2^2)^x = (2^3)^(2-x)
2^(2*x) = 2^[3(2-x)]
2x = 3(2-x)
2x = 6 -3x
2x +3x = 6
5x = 6
x = 6/5 ---------answer.
Check,
4^x = 8^(2-x)
4^(6/5) =? 8^(2 -6/5)
4^(1.2) =? 8^(0.8)
Using a calculator,
5.278031643 =? 5.278031643
Yes, so, OK.